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ve 36" we will need 3 of above one foot fenders in addition in order to achieve 10" W (of C Marine) we will need double rows (2x) 5616" Length from C Marine / 12" = 468 1 foot pieces then we must double to achieve same Width = 936 x 13.25 per fender = 12,402 cost before end pieces / bolts / washers questions
ideration was that if we proceed with new pattern (first one below) we will only require the following pieces per Carlos If we keep use new pattern C Marine Savings would be 156 - 114 fenders — 42 x 176.73 = 7,422.66 Date: June 3, 2015 at 3:16:13 PM EDT From: Carlos Rodriguez < Reply-To: Carlos Rodri uez To:
2 mentions1 same-page
Page ?Same page
ve 36" we will need 3 of above one foot fenders in addition in order to achieve 10" W (of C Marine) we will need double rows (2x) 5616" Length from C Marine / 12" = 468 1 foot pieces then we must double to achieve same Width = 936 x 13.25 per fender = 12,402 cost before end pieces / bolts / washers questions
ideration was that if we proceed with new pattern (first one below) we will only require the following pieces per Carlos If we keep use new pattern C Marine Savings would be 156 - 114 fenders — 42 x 176.73 = 7,422.66 Date: June 3, 2015 at 3:16:13 PM EDT From: Carlos Rodriguez < Reply-To: Carlos Rodri uez To:
2 mentions1 same-page
Page ?Same page
ve 36" we will need 3 of =bove one foot fenders in addition in order to =chieve 10" W (of C Marine) we will need double rows =2x) 5616"=Length from C Marine / 12" = 468 1 foot pieces then we must double to =chieve same Width = 936 x 13.25 per fender = 12,402 =ost before end pieces / bolts / washers questions
ideration was that if we proceed with new =attern (first one below) we will only require the following pieces per =arlos If we keep use new pattern C Marine Savings =ould be 156. 114 fenders = 42 x 176.73 = 7,422.66 Date: June 3, 2015 at 3:16:13 PM EDT From: Carlos Rodriguez Reply-To: Carlos Rodriguez querinla
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2 mentions1 same-page
Page ?Same page
ve 36" we will need 3 of =bove one foot fenders in addition in order to =chieve 10" W (of C Marine) we will need double rows =2x) 5616"=Length from C Marine / 12" = 468 1 foot pieces then we must double to =chieve same Width = 936 x 13.25 per fender = 12,402 =ost before end pieces / bolts / washers questions
sideration was that if we proceed with new =attern (first one below) we will only require the following pieces per =arlos If we keep use new pattern C Marine Savings =ould be 156 - 114 fenders = 42 x 176.73 = 7,422.66 Date: June 3, 2015 at 3:16:13 PM EDT From: Carlos Rodriguez Reply-To: Carlos Rodriguez To: Ri
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Mutual Connections (20)
Entities connected to both C Marine / 12 and C Marine Savings
Jeffrey Epstein
PERSON4 w/ C·4 w/ C
Alfredo Rodriguez
PERSON4 w/ C·4 w/ C
Richard Kahn
PERSON4 w/ C·4 w/ C
Carlos
PERSON4 w/ C·4 w/ C
CR
Carlos Rodriguez
PERSON4 w/ C·4 w/ C
Marc Rich
PERSON3 w/ C·3 w/ C
Michael C
PERSON3 w/ C·3 w/ C
C Marine
ORGANIZATION3 w/ C·3 w/ C
LB
Leon Black
PERSON2 w/ C·2 w/ C
Lesley Groff
PERSON2 w/ C·2 w/ C
Concord
LOCATION2 w/ C·2 w/ C
Milwaukee
LOCATION2 w/ C·2 w/ C
Clearwater
LOCATION2 w/ C·2 w/ C
DW
Daphne Wallace
PERSON2 w/ C·2 w/ C
St James
LOCATION2 w/ C·2 w/ C
DF
Dock Fenders
PERSON2 w/ C·2 w/ C
Grey ) S/Williams
ORGANIZATION2 w/ C·2 w/ C
FOB Concord MI
ORGANIZATION2 w/ C·2 w/ C
Tropicana Shipping
ORGANIZATION2 w/ C·2 w/ C
Dock Fender
ORGANIZATION2 w/ C·2 w/ C